(w/w-3)-(4w/4w-5)=(w-5/4w^2-17w+15)

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Solution for (w/w-3)-(4w/4w-5)=(w-5/4w^2-17w+15) equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w/w-(((4*w)/4)*w)-3+5 = w-((5/4)*w^2)-(17*w)+15 // - w-((5/4)*w^2)-(17*w)+15

(5/4)*w^2-(((4*w)/4)*w)-w+17*w+w/w-15-3+5 = 0

(5/4)*w^2-w^2-w+17*w+w/w-15-3+5 = 0

1/4*w^2+16*w-12 = 0

DELTA = 16^2-(-12*1/4*4)

DELTA = 268

DELTA > 0

w = (268^(1/2)-16)/(1/4*2) or w = (-268^(1/2)-16)/(1/4*2)

w = 2*(2*67^(1/2)-16) or w = 2*(-2*67^(1/2)-16)

w in { 2*(-2*67^(1/2)-16), 2*(2*67^(1/2)-16) }

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